While performing a thermodynamics experiment, a student made the following observation.
HCl + NaOH → NaCl + H2O = -57.3 kJ mol?1
CH3COOH + NaOH → CH3COONa + H2O = -55.3 kJ mol-1
The enthalpy of ionization of CH3COOH as calculated by the student is _________kJ mol-1. (nearest integer)
While performing a thermodynamics experiment, a student made the following observation.
HCl + NaOH → NaCl + H2O = -57.3 kJ mol?1
CH3COOH + NaOH → CH3COONa + H2O = -55.3 kJ mol-1
The enthalpy of ionization of CH3COOH as calculated by the student is _________kJ mol-1. (nearest integer)
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry Ncert Solutions Class 11th 2023
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