While performing a thermodynamics experiment, a student made the following observation.

HCl + NaOH → NaCl + H₂O $\Delta H$  = -57.3 kJ mol^?1

CH₃COOH + NaOH → CH₃COONa + H₂O $\Delta H$  = -55.3 kJ mol^-1

The enthalpy of ionization of CH₃COOH as calculated by the student is _________kJ mol^-1. (nearest integer)

<p><span contenteditable="false"> <math> <mrow> <mi>Δ</mi> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mi>i</mi> <mi>o</mi> <mi>n</mi> <mi>i</mi> <mi>z</mi> <mi>a</mi> <mi>t</mi> <mi>i</mi> <mi>o</mi> <mi>n</mi> </mrow> </msub> <mi>o</mi> <mi>f</mi> <mtext> </mtext> <mtext> </mtext> <mi>C</mi> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msub> <mi>C</mi> <mi>O</mi> <mi>O</mi> <mi>H</mi> <mo>=</mo> <mo>−</mo> <mn>5</mn> <mn>5</mn> <mo>.</mo> <mn>3</mn> <mrow> <mo> (</mo> <mrow> <mo>−</mo> <mn>5</mn> <mn>7</mn> <mo>.</mo> <mn>3</mn> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p><p>= 2 KJ/mole</p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment