Why is the C—O—H bond angle in alcohols slightly less than the tetrahedral angle whereas the C—O—C bond angle in ether is slightly greater?

<p><span data-teams="true">This is a short answer type question as classified in NCERT Exemplar</span></p><p>The bond angle C—O—H in alcohols is less than tetrahedral angle because of the repulsion between the lone pairs present on the oxygen atom, which pushes the bond C—O—H closer. Therefore, &nbsp; C—O—H bond angle in alcohols is slightly less than the tetrahedral angle.</p><p>In&nbsp; ethers, the lone pairs on oxygen atoms are also present but the two bulky alkyl groups also have repulsive force which increases the C—O—C bond angle. Therefore, &nbsp; the C—O—C bond angle in ether is slightly greater than tetrahedral angle .</p>

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