Directions for questions: Read the information carefully and answer the questions given below.
A company has seven tasks to complete. They are:
T1 – Buy raw material
T2 – Take orders
T3 – Process raw material
T4 – Deliver finish product
T5 – Hire new recruits
T6 – Pay the bills
T7 – Pay salary
And to do these tasks it has only two days, Monday and Tuesday. Certain conditions should be followed:
The Company must do at least two tasks each day.
The company cannot start its task on Monday with T4 (deliver finish product)
Task T1 should be done either in the beginning or at the end of any of the two days. Task T3 and task T7 should be done on the same day with no task done in between them. Task T4 and task T6 cannot be done on same day.
At least one task should be done in between the task T2 and task T7.
Which of the following is an acceptable schedule that the company might follow in the two days?
Monday Tuesday
Directions for questions: Read the information carefully and answer the questions given below.
A company has seven tasks to complete. They are:
T1 – Buy raw material
T2 – Take orders
T3 – Process raw material
T4 – Deliver finish product
T5 – Hire new recruits
T6 – Pay the bills
T7 – Pay salary
And to do these tasks it has only two days, Monday and Tuesday. Certain conditions should be followed:
The Company must do at least two tasks each day.
The company cannot start its task on Monday with T4 (deliver finish product)
Task T1 should be done either in the beginning or at the end of any of the two days. Task T3 and task T7 should be done on the same day with no task done in between them. Task T4 and task T6 cannot be done on same day.
At least one task should be done in between the task T2 and task T7.
Which of the following is an acceptable schedule that the company might follow in the two days?
Monday Tuesday
Option 1 -
T3, T7 T1, T2, T4, T5, T6
Option 2 -
T6, T5, T2 T7, T3, T4, T1
Option 3 -
T3, T6, T7, T1 T4, T2, T5
Option 4 -
T7, T3, T6, T5 T4, T2, T1
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1 Answer
-
Correct Option - 4
Detailed Solution:Only option (d) does not violate any of the given conditions.
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Please find the answer below
From the 1st statement: B2 is now as old as B3 was in the past. Hence B2 is younger to B3 or B2 < B3. Also sometime in the past B1 was twice as old as B4. So B1 is elder to B4 or B1 > B4. B3 will be as old as B5 in future, hence B3 < B5. The second statement suggests: B1 > B6. B1 was as old as B7 in the past. Hence B1 > B7. B4 will be as old as B6 in future. Hence B6 > B4. B6 will be as old as B7 now in future. Hence B7 > B6. B7 was as old as B2, when B1 was as old as B7. Hence B1 = B2. Combining both the results, we get: and B5 > B3 > B2 = B1 > B7 > B6 > B4 (Note by B1 = B2, it is meant that they are of similar age group, not necessarily the same).
B5 is the eldest brother.
According to the information provided following arrangement will be obtained:
(K→ Kerala ; G → Goa ; D → Delhi)
Order according to height | Student | Belong | |||||||||
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| K | G | D |
× | × | × | × | × | × | × | √ | Arun | × | × | √ |
× | × | √ | × | × | × | × | × | Ajit | √ | × | × |
√ | × | × | × | × | × | × | × | Rohan | √ | × | × |
× | × | × | × | × | √ | × | × | Gajraj | × | √ | × |
× | √ | × | × | × | × | × | × | Ronit | × | × | √ |
× | × | × | × | √ | × | × | × | Shubham | √ | × | × |
× | × | × | × | × | × | √ | × | Sweety | × | √ | × |
× | × | × | √ | × | × | × | × | Lovely | × | √ | × |
Looking at the table given in the first question of the set, we get that Talwar lives on the sixth floor.
The data available is not enough to determine where Rubi belongs to. The given data is insufficient to answer the above question.
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