Two traders, T1 and T2, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs. 100, while at the end of the fifth day it was priced at Rs. 110. At the end of each day, the MCS share price either went up by Rs. 10, or else, it came down by Rs. 10. Both T1 and T2 took buying and selling decisions at the end of each trading day.

The beginning price of MCS share on a given day was the same as the ending price of the previous day.

T1 and T2 started with the same number of shares and amount of cash, and had enough of both. Below are some additional facts about how T1 and T2 traded over the five trading days.

Each day if the price went up, T1 sold 10shares of MCS at the closing price. On the other hand, each day if the price went down, he bought10 shares at the closing price.

If on any day, the closing price was above Rs.110, then T2 sold 10 shares of MCS, while if it was below Rs. 90, he bought 10 shares, all at the closing price.

If T2 ended up with 20 more shares than T1 at the end of day 5, what was the price of the share at the end of day 3?

Option 1 - Rs.90

Option 2 - Rs. 100

Option 3 - Rs. 110

Option 4 - Rs. 120

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Answered by

Payal Gupta | Contributor-Level 10

7 months ago

Correct Option - 1

Detailed Solution:

	Day 1	Day 2	Day 3	Day 4	Day 5
Start Price	100	90	80	90	100
End Price	90	80	90	100	110

Assume initial number of share with T1 and T2 is X. In the above table T1 by 10 share each on day 1, day 2 and sold 10 shares and day 3, day 4 and day 5.

Total share with T1 is X – 10.

In the above T2 buy share only on day 2.

Total shares with T2 is X + 10.

T2 had 20 shares more than T1.

Therefore at th

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From the 1st statement: B2 is now as old as B3 was in the past. Hence B2 is younger to B3 or B2 < B3. Also sometime in the past B1 was twice as old as B4. So B1 is elder to B4 or B1 > B4. B3 will be as old as B5 in future, hence B3 < B5. The second statement suggests: B1 > B6. B1 was as old as B7 in the past. Hence B1 > B7. B4 will be as old as B6 in future. Hence B6 > B4. B6 will be as old as B7 now in future. Hence B7 > B6

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Order according to height								Student	Belong
1	2	3	4	5	6	7	8		K	G	D
×	×	×	×	×	×	×	√	Arun	×	×	√
×	×	√	×	×	×	×	×	Ajit	√	×	×
√	×	×	×	×	×	×	×	Rohan	√	×	×
×	×	×	×	×	√	×	×	Gajraj	×	√	×
×	√	×	×	×	×	×	×	Ronit	×	×	√
×	×	×	×	√	×	×	×	Shubham	√	×	×
×	×	×	×	×	×	√	×	Sweety	×	√	×
×	×	×	√	×	×	×	×	Lovely	×	√	×