15.
15.
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1 Answer
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We know that.
sin 3θ =3 sin θ 4sin3θ (identity).
(E) Let x = sinθ. Then, sin −1x=θ . We have,
Sin3 (sin −1x) = 3x−4x3
3sin −1x =sin-1 (3x−4x3)
Hence proved.
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