25. A manufacturer makes two types of toys, A and B. Three machines are needed for this purpose, and the time (in minutes) required for each toy on the machines is given below:
Types of Toys
Machines
I
II
III
A
12
18
6
B
6
0
9
Each machine is available for a maximum of 6 hours per day. If the profit on each toy of type A is ?. 7.50 and that on each toy of type B is ?. 5, show that 15 toys of type A and 30 of type B should be manufactured in a day to get maximum profit.
25. A manufacturer makes two types of toys, A and B. Three machines are needed for this purpose, and the time (in minutes) required for each toy on the machines is given below:
Types of Toys |
Machines |
||
I |
II |
III |
|
A |
12 |
18 |
6 |
B |
6 |
0 |
9 |
Each machine is available for a maximum of 6 hours per day. If the profit on each toy of type A is ?. 7.50 and that on each toy of type B is ?. 5, show that 15 toys of type A and 30 of type B should be manufactured in a day to get maximum profit.
-
1 Answer
-
Let x and y toys of type A and type B be manufactured in a day, respectively.
The given problem can be formulated as given below:
Subject to the constraints,
The feasible region determined by the constraints is given below:
A (20, 0), B (20, 20), C (15, 30) and D (0, 40) are the corner points of the feasible region.
The values of z at these corner points are given below:
Corner Point
z = 7.5x + 5y
A (20, 0)
150
B (20, 20)
250
C (15, 30)
262.5
Maximum
D (0, 40)
200
262.5 at (15, 30) is the maximum value of z.
Hence, the manufacturer should manufacture 15 toys of type A and 30 toys of type B to maximise the profit.
Similar Questions for you
= -8 (-3 + k)
For inconsistent
. (ii)
by using property
Adding (i) and (ii) we get 2l =
Given 2x + y – z = 3 . (i)
x – y – z = α . (ii)
3x + 3y + βz = 3 . (iii)
(i) x 2 – (ii) – (iii) – (1 + β) z = 3 - α
For infinite solution 1 + β = 0 = 3 - α
=> α = 3, β = -1
So, α + β - αβ = 5
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers