25. Show that points
A (a, b + c), B (b, c + a), C (c, a + b) are collinear.
25. Show that points
A (a, b + c), B (b, c + a), C (c, a + b) are collinear.
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1 Answer
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The area of triangle from by the given points is area ( ΔABC) =
C1→ C1 + C2 + C3
Taking (a + b + c + 1) common from C1
= 0
Hence the points A, B C are collinear.
Similar Questions for you
|2A| = 27
8|A| = 27
Now |A| = α2–β2 = 24
α2 = 16 + β2
α2– β2 = 16
(α–β) (α+β) = 16
->α + β = 8 and
α – β = 2
->α = 5 and β = 3
|A| = 3
|B| = 1
->|C| = |ABAT| = |A|B|A7| = |A|2|B|
= 9
->|X| = |A|C|2|AT|
= 3 * 92 * 3 = 9 * 92 = 729
|A| = 2
->
->, m ¬ even
7
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