6. Minimise Z = x + 2y subject to 2x + y ≥ 3, x + 2y ≥ 6, x, y ≥ 0.
6. Minimise Z = x + 2y subject to 2x + y ≥ 3, x + 2y ≥ 6, x, y ≥ 0.
Minimize
Subject to
The corresponding equation of the given inequalities are

The feasible region is unbounded the corner point are A (6,0), B (0,3)
The value of Z at these corner points are follows.

Since, the feasible region is unbounded, a graph of is drawn.
Also since there is no point common in fea
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Maths Ncert Solutions class 12th 2026
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