A line is drawn from a point P(x, y) on curve y = f(x), making an angle in anti-clockwise with the +ve x-axis which is supplementary to the one made by the tangent to the curve at P(x, y). The line meets the x-axis at A. Another line perpendicular to the first, is drawn from P(x, y) meeting the y-axis at B. If OA = OB, where O is the origin, then the curve which passes through (1, 1).

Option 1 -

x2 – y2 + 4xy = 4

Option 2 -

x2 – y2 – 2xy + 2 = 0        

Option 3 -

x2 – y2 + 2xy = 2

Option 4 -

x2 – y2 – 4xy + 4 = 0

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 weeks ago
    Correct Option - 3


    Detailed Solution:

    The equation of the line through P (x, y) making an angle with the x-axis which is supplementary to the angle made by the tangent at P (x, y) is

    Y y = d y d x ( X x )                    …. (1)

    At the point where it meets the x-axis

    Y = 0, X = x    + y d y d x O A = x + y d y d x    …. (2)

    The line through P (x, y) and perpendicular to (1) is

    Y y = d x d y ( X x )           

    At the point where it meets the y-axis

    X = 0 , Y = y = x d y d x O B = y x d y d x           .

    x 2 + 2 x y y 2 = 2            

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