A pole stands vertically inside a triangular park ABC. Let the angel of elevation of the top of the pole from each corner of the park be π/3. If the radius of the circumcircle of ?ABC is 2, then the height of the pole is equal to :
A pole stands vertically inside a triangular park ABC. Let the angel of elevation of the top of the pole from each corner of the park be π/3. If the radius of the circumcircle of ?ABC is 2, then the height of the pole is equal to :
Option 1 -
1/√3
Option 2 -
√3
Option 3 -
2√3
Option 4 -
2√3/3
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:Given a right-angled triangle with one angle π/3 (or 60°), and the side adjacent to it is h/2.
Using the tangent function: tan (π/3) = opposite / adjacent.
Let the adjacent side be 2. Then tan (π/3) = h/2.
We know tan (π/3) = √3.
So, h/2 = √3, which implies h = 2√3.
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