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Let A = ( 1 − 1 0 0 1 − 1 0 0 1 ) a n d     B = 7 A 2 0 − 2 0 A 7 + 2 I ,  where I is an identity matrix of order 3 × 3. If B = [ b i j ] ,  then b13 is equal to……………

0 3 Views | Posted a month ago
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  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    a month ago

    A = [ 1 − 1 0 0 1 − 1 0 0 1 ]

    B = 7A20 – 20A7 + 2l

    A 2 [ 1 − 1 0 0 1 − 1 0 0 1 ] [ 1 − 1 0 0 1 − 1 0 0 1 ] = [ 1 − 2 1 0 1 − 2 0 0 1 ]

    A 3 = [ 1 − 2 1 0 1 − 2 0 0 1 ] [ 1 − 1 0 0 1 − 1 0 0 1 ] = [ 1 − 3 3 0 1 − 3 0 0 1 ]

    A 4 = [ 1 − 3 3 0 1 − 3 0 0 1 ] [ 1 − 1 0 0 1 − 1 0 0 1 ] = [ 1 − 4 6 0 1 − 4 0 0 1 ]

    a 1 3     o f     A , A 2 , A 3 , . . . . . . .

    are 0, 1, 3, 6,.

    For 0, 1, 3, 6, .

    S n = 0 + 1 + 3 + 6 + . . . . + t n

    S n = 0 + + 3 + . . . . + t n − 1 + t n

    t n = 1 + 2 + 3 + . . . + ( t n − t n − 1 )

    = ( n − 1 ) . n 2

    b 1 3 = 7 ( 1 9 0 ) − 2 0 ( 2 1 ) + 0

    = 1330 – 420 = 910

     

     

     

     

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