Let a = 2i - 3j + 4k and b = 7i + j - 6k. If r * a = r * b, r ⋅ (i + 2j + k) = -3, then r ⋅ (2i - 3j + k) is equal to:
Let a = 2i - 3j + 4k and b = 7i + j - 6k. If r * a = r * b, r ⋅ (i + 2j + k) = -3, then r ⋅ (2i - 3j + k) is equal to:
Option 1 - <p>10</p>
Option 2 - <p>12</p>
Option 3 - <p>8</p>
Option 4 - <p>13</p>
46 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
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Answered by
5 months ago
Correct Option - 2
Detailed Solution:
Given r * a = r * b, which means r * a - r * b = 0 ⇒ r * (a - b) = 0.
This implies that vector r is parallel to vector (a - b).
So, r = λ (a - b) for some scalar λ.
a - b = (2i - 3j + 4k) - (7i + j - 6k) = -5i - 4j + 10k.
So, r = λ (-5i - 4j + 10k).
We are also given r ⋅ (i + 2j + k) = -3.
λ (-5i - 4j + 1
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