Let f: R → R be a function such that f(2) = 4 and f'(2) = 1. Then the value of lim(x→2) (x²f(2) - 4f(x))/(x-2) is equal to:

Option 1 - 12

Option 2 - 4

Option 3 - 16

Option 4 - 8

2 Views|Posted 7 months ago

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7 months ago

Correct Option - 1

Detailed Solution:

Using L'Hopital Rule:
lim (x→2) (2xf (2) - 4f' (x)/1 = 2 (2)f (2) - 4f' (2) = 4 (4) - 4 (1) = 12.

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