Let f: R → R be a function such that f(2) = 4 and f'(2) = 1. Then the value of lim(x→2) (x²f(2) - 4f(x))/(x-2) is equal to:
Let f: R → R be a function such that f(2) = 4 and f'(2) = 1. Then the value of lim(x→2) (x²f(2) - 4f(x))/(x-2) is equal to:
Option 1 -
12
Option 2 -
4
Option 3 -
16
Option 4 -
8
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:Using L'Hopital Rule:
lim (x→2) (2xf (2) - 4f' (x)/1 = 2 (2)f (2) - 4f' (2) = 4 (4) - 4 (1) = 12.
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