Let S = {n ∈ N | [n,i;0,1][a,b;c,d] = [a,b;c,d] ∀ a,b,c,d ∈ R}, where i = √-1. Then the number of 2-digit numbers in the set S is …….

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    Answered by

    Raj Pandey | Contributor-Level 9

    a month ago

    S = {n ∈ N | [n i; 0 1] [a b; c d] = [a b; c d] ∀a, b, c, d ∈ R}
    [na+ic, nb+id; c, d] = [a, b;c, d]
    This must be an identity matrix. n=1. The question seems to have typos. Let's follow the solution logic.
    The solution implies the matrix must be [1 0; 0 1] or [-1 0; 0 -1]. And n must be a multiple of 8.
    2-digit multiples of 8 are 16, 24, ., 96. Total 11 numbers.

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A
alok kumar singh

R1 = { (1, 1) (1, 2), (1, 3)., (1, 20), (2, 2), (2, 4). (2, 20), (3, 3), (3, 6), . (3, 18),
(4, 4), (4, 8), . (4, 20), (5, 5), (5, 10), (5, 15), (5, 20), (6, 6), (6, 12), (6, 18), (7. 7),
(7, 14), (8, 8), (8, 16), (9, 9), (9, 18), (10, 10), (10, 20), (11, 11), (12, 12), . (20, 20)}

n (R1) = 66

R2 = {a is integral multiple of b}

So n (R1 – R2) = 66 – 20 = 46

as R1 Ç R2 = { (a, a) : a Î s} = { (1, 1), (2, 2), ., (20, 20)}

A
alok kumar singh

g o f ( x ) = { f ( x ) , f ( x ) < 0 f ( x ) , f ( x ) > 0

= { e l n x = x ( 0 , 1 ) e x ( , 0 ) l n x ( 1 , )

Therefore, gof (x) is many one and into

A
alok kumar singh

  ?  R is symmetric relation

⇒   (y, x) R V (x, y) R

(x, y)  R 2x = 3y and (y, x) R 3x = 2y

Which holds only for (0, 0)

Which does not belongs to R.

Value of n = 0

A
alok kumar singh

f is increasing function

x < 5x < 7x

f (x) < f (5x) < f (7x)

  f ( x ) f ( x ) < f ( 5 x ) f ( x ) < f ( 7 x ) f ( x )           

l i m x f ( x ) f ( x ) < l i m x f ( 5 x ) f ( x ) < l i m x f ( 7 x ) f ( x )             

-> 1 < l i m x f ( 5 x ) f ( x ) < 1 l i m x f ( 5 x ) f ( x ) = 1

l i m x ( f ( 5 x ) f ( x ) 1 ) = 0            

A
alok kumar singh

Given f (k) = { k + 1 , k i s o d d k , k i s e v e n

  ? g : A A           such that g (f (x) = f (x)

Case I : If x is even then g (x) = x . (i)

Case II : If x is odd then g (x + 1) = x + 1 . (ii)

From (i) & (ii), g (x) = x, when x is even

So total no. of functions = 105 × 1 = 105

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