Let x̄ be a vector in the plane containing vectors ā = 2i - j + k and b̄ = i + 2j - k. If the vector x̄ is perpendicular to (3i + 2j - k) and its projection on ā is (17√6)/2, then the value of |x̄|² is equal to ______.
Let x̄ be a vector in the plane containing vectors ā = 2i - j + k and b̄ = i + 2j - k. If the vector x̄ is perpendicular to (3i + 2j - k) and its projection on ā is (17√6)/2, then the value of |x̄|² is equal to ______.
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1 Answer
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Let x = m(a + λb).
Given m(a + λb) ⋅ (3i + 2j - k) = 0, which leads to λ = -3/8.The projection of vector x on vector a is given by x ⋅ â, where â is the unit vector of a.
Projection = (x ⋅ a) / |a| = 17√6 / 2
x ⋅ a = (m(a + λb)) ⋅ a = m(a ⋅ a + λ(b ⋅ a)) = m(|a|^2 + λ(b ⋅ a))The provided text simplifies this to:
m(6 - 3/8 * (-1)) = 17√6 / 2
m * (51/8) = 17 * 6 / 2 (The text seems to have a typo 17x6/2 instead of 17√6 / 2)
Assuming it is 17 * 6 / 2, m * 51/8 = 51, so m = 8.x = 8(a + (-3/8)b) = 8a - 3b
x = 8( (13/8)i - (14/8)j + (11/8...more
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