The angle of elevation of a cloud C from a point P,200m above a still take is 30 . If the angle of depression of the image of C in the lake from the point P is 60 , then PC (in m ) is equal to

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mn>200</mn> <mroot> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> <mrow></mrow> </mroot> </math> </span></p>
Option 2 - <p>&nbsp;100</p>
Option 3 - <p>400</p>
Option 4 - <p><strong>&nbsp;</strong><span class="mathml" contenteditable="false"> <math> <mn>400</mn> <mroot> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> <mrow></mrow> </mroot> </math> </span>(Trigonometry)</p>
3 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
A
8 months ago
Correct Option - 3
Detailed Solution:

 r=020?50-rC6=50C6+49C6+48C6+.+30C6

=50C6+49C6+48C6+.+30C6+30C7-30C7=50C6+49C6+48C6+.+31C6+31C7-30C7=50C6+50C7-30C7=51C7-30C7

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

cos115=cot112

tan (2 (tan112+cot112))+tan1 (12)=tan (π+tan112)=12

tan2α=222tanα1tan2α=22

2tan2α+tanα2=0

tanα=12, (2)rejected

03? g (x)-f (x)=03? ||x-2|-2|dx-03? |x-2|dx

=12×2×2+1+12×1×1-12×2×2+12×1×1

=2+1+12-2+12=1

  (pq) (pr)

(pq) (pr)

(A) (q) (pr) (B) (p) (pr)

(C) (pr) (pq) (D) (pq)r

Option (D) is correct

K-2h-11-23-1=-1K=2h

? [? ABC]=55

12 (5) (h-1)2+ (K-2)2=55

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Maths NCERT Exemplar Solutions Class 12th Chapter Twelve 2025

Maths NCERT Exemplar Solutions Class 12th Chapter Twelve 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering