The equation of a common tangent to the parabolas y = x2 and y = -(x – 2)2
is
The equation of a common tangent to the parabolas y = x2 and y = -(x – 2)2 is
Option 1 -
y = 4(x – 2)
Option 2 -
y = 4(x – 1)
Option 3 -
y = 4(x + 1)
Option 4 -
y = 4(x + 2)
Asked by Shiksha User
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1 Answer
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Correct Option - 2
Detailed Solution:Equation of tangent of slope m to y = x2 is y = mx -
Equation of tangent of slope m to y = - (x - 2)2 is y = m (x – 2) +
If both equation represent the same line therefore on comparing (i) and (ii) we get m = 0, 4
therefore equation of tangent is y = 4x – 4
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