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System of Particles and Rotational Motion physics ncert solutions class 11th Physics Class 11th

The angular speed of a fly wheel moving with uniform angular acceleration changes from 1200rpm to 3120 in 16 seconds. The angular acceleration in $r a d / s^{2}$ is:

Option 1 -

$2 π$

Option 2 -

$4 π$

Option 3 -

$12 π$

Option 4 -

$104 π$

2 Views | Posted 4 weeks ago

Asked by Shiksha User

1 Answer

Answered by

Raj Pandey | Contributor-Level 9

4 weeks ago

Correct Option - 2

Detailed Solution:

$\begin{array}{r} ω = ω_{0} + α t \\ α = \frac{ω - ω_{0}}{t} \\ = \frac{(3120 - 1200)}{16 s} r p m \\ = \frac{1920}{16} \times \frac{2 π}{60} r a d / s^{2} \\ = 4 π r a d / s^{2} \end{array}$

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The angular speed of a fly wheel moving with uniform angular acceleration changes from 1200rpm to 3120 in 16 seconds. The angular acceleration in $r a d / s^{2}$ is:

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The angular speed of a fly wheel moving with uniform angular acceleration changes from 1200rpm to 3120 in 16 seconds. The angular acceleration in r a d / s 2 is:

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The angular speed of a fly wheel moving with uniform angular acceleration changes from 1200rpm to 3120 in 16 seconds. The angular acceleration in $r a d / s^{2}$ is: