10.2 Explain why

(a) The angle of contact of mercury with glass is obtuse, while that of water with glass is acute

(b) Water on a clean glass surface tends to spread out while mercury on the same surface tends to form drops. (Put differently, water wets glass while mercury does not)

(c) Surface tension of a liquid is independent of the area of the surface

(d) Water with detergent dissolved in it should have small angles of contact

(e) A drop of liquid under no external forces is always spherical in shape

0 7 Views | Posted 5 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    5 months ago

    The angle between the tangent to the liquid surface at the point of contact and the surface inside the liquid is called the angle of contact ( θ) , as shown in the diagram

    Sla = Interfacial tension between liquid-air interface

    Ssl = Interfacial tension between solid -liquid interface

    Ssa = Interfacial tension between solid-air interface

    At the line of contact of contact, the surface forces between the three media must be in equilibrium. Hence

    cos?θ = Ssa-SlaSla

    The angle of contact θ is obtuse, if Ssa<Sla , as in the case of mercury on glass

    This angle is acute if Ssl<Sla , as in the case of water on glass

    Mercury molecules (which mak

    ...more

Similar Questions for you

S
Swayam Gupta

Surface tension is the force acting on the surface of the liquid.

S
Swayam Gupta

Bernoulli's principle states that in a steady flow, the sum of pressure, kinetic energy per unit volume, and potential energy per unit volume remains constant.

S
Swayam Gupta

Yes, the Mechanical properties of fluids class 11th physics is important in NEET. On average, 1-2 questions would be asked from this chapter, which you can cover from the Class 11th Mechanical Properties of Fluids notes.

S
Swayam Gupta

The main mechanical properties of fluids are exerting pressure, resisting flow or viscosity, forming surface tension, following Bernoulli's principle, and moving in a streamline.

V
Vishal Baghel

Since velocity does not change, so acceleration will be zero.

mg = FB + Fv 4 π 3 r 3 ρ g = 4 π 3 r 3 σ g + 6 π η r v

v = 2 r 2 ( ρ σ ) g 9 η = 2 × 0 . 1 × 0 . 1 × 1 0 6 × ( 1 0 4 1 0 3 ) × 1 0 9 × 1 . 0 × 1 0 5

h = 4 0 0 2 g = 2 0 m

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 686k Reviews
  • 1800k Answers

Learn more about...

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post