10.27 A plane is in level flight at constant speed and each of its two wings has an area of 25 m2. If the speed of the air is 180 km/h over the lower wing and 234 km/h over the upper wing surface, determine the plane’s mass. (Take air density to be 1 kg m–3).

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    Vishal Baghel | Contributor-Level 10

    5 months ago

    The area of the wing of the plane, A = 2 ×25m2 = 50 m2

    Speed of air over the lower wing, V1 = 180 km/h = 50 m/s

    Speed of air over the upper wing, V2 = 234 km/h = 65 m/s

    Density of air, ρ = 1 kg/ m3

    Let us assume, pressure over the lower wing = P1 and pressure over the upper wing = P2

    The upward force on the plane can be obtained using Bernoulli’s equation:

    On lower wing= P1 + 12ρV12 , On upper wing = P2 + 12ρV22

    From equilibrium of momentum

    P1 + 12ρV12 = P2 + 12ρV22

    P1 - P2)=12ρ(V22-V12 )

    The net upward force = ( P1 - P2)A = 12ρ(V22-V12 ) 

    ...more

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