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physics ncert solutions class 11th Physics Class 11th Thermal Properties of Matter

11.1 The triple points of neon and carbon dioxide are 24.57 K and 216.55 K respectively. Express these temperatures on the Celsius and Fahrenheit scales.

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Payal Gupta | Contributor-Level 10

5 months ago

11.1 Kelvin and Celsius scales are related as

$T_{c}$ = $T_{k}$ - 273.15 ….(i),

Where $T_{c} =$ temperature in Celsius scale and $T_{k}$ = temperature in Kelvin scale

Celsius and Fahrenheit scales are related as

$\frac{T_{c}}{5}$ = $\frac{T_{f} - 32}{9}$ , where $T_{f}$ = temperature in Fahrenheit scale

(a) For Neon, $T_{k}$ = 24.57. Hence $T_{c}$ = 24.57 – 273.15 = -248.58 degree Celsius

$T_{f} = \frac{9}{5} \times T_{c} + 32$ = $\frac{9}{5} \times (- 248.58) + 32$ = -415.44 degree Fahrenheit

(b) For Carbon dioxide, $T_{k}$ = 216.55. Hence $T_{c}$ = 216.55 – 273.15 = -56.6 degree Celsius

$T_{f} = \frac{9}{5} \times T_{c} + 32$ = $\frac{9}{5} \times (- 56.6) + 32$ = -69.88 degree Fahrenheit

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This is a multiple choice answer as classified in NCERT Exemplar

(b), (c), (d) When the hot milk in the table is transferred to the surroundings by conduction, convection and radiation.

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11.1 The triple points of neon and carbon dioxide are 24.57 K and 216.55 K respectively. Express these temperatures on the Celsius and Fahrenheit scales.

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