11.3 The electrical resistance in ohms of a certain thermometer varies with temperature according to the approximate law :
R = Ro [1 + α(T – )]
The resistance is 101.6 Ω at the triple-point of water 273.16 K, and 165.5 Ω at the normal melting point of lead (600.5 K). What is the temperature when the resistance is 123.4 Ω ?
11.3 The electrical resistance in ohms of a certain thermometer varies with temperature according to the approximate law :
R = Ro [1 + α(T – )]
The resistance is 101.6 Ω at the triple-point of water 273.16 K, and 165.5 Ω at the normal melting point of lead (600.5 K). What is the temperature when the resistance is 123.4 Ω ?
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1 Answer
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11.3 It is given that R = [1 + α(T – )] ………(i)
Where Ro and To are the initial resistance and temperature and R and T are the final resistance and temperature.
At the triple point of water, To = 273.15 K, = 101.6 Ω
At normal melting point of lead, T = 600.5 K, R = 165.5 Ω
Substituting these values in equation (i), we get
165.5 = [1 + α(600.5 – )]
= 1 + 327.35 α, or α = = 1.92
When R = 123.4 Ω, T can be calculated as
123.4 = [1 + 1.92 (T – )]
1.214 =
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