12.5 In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case ?
(Take 1 cal = 4.19 J)
12.5 In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case ?
(Take 1 cal = 4.19 J)
The work done, W = 22.3 J
Being an adiabatic process, Q = 0
W = -22.3 J : since the work is done on the system
From the 1st law of thermodynamics, we know Q = W, where is the change of internal energy of the gas
U = 22.3 J
When the gas goes from state A to state B via a process, the net heat abso
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From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Heat is path dependent so path function but internal energy does not depend on path chosen.
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physics ncert solutions class 11th 2023
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