12.5 In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case ?
(Take 1 cal = 4.19 J)
12.5 In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case ?
(Take 1 cal = 4.19 J)
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1 Answer
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The work done, W = 22.3 J
Being an adiabatic process, Q = 0
W = -22.3 J : since the work is done on the system
From the 1st law of thermodynamics, we know Q = W, where is the change of internal energy of the gas
U = 22.3 J
When the gas goes from state A to state B via a process, the net heat absorbed by the system is:
Q = 9.35 cal = 9.35 J = 39.1765 J
Heat absorbed Q = W
W = Q - = 39.1765 – 22.3 = 16.8765 J
Therefore, work done by the system is 16.8765 J
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