13.14 The nucleus decays by emission. Write down the -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that:
m ( = 22.994466 u
m ( = 22.989770 u.
13.14 The nucleus decays by emission. Write down the -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that:
m ( = 22.994466 u
m ( = 22.989770 u.
13.14 In emission, the number of protons increase by 1 and one electron and an antineutrino are emitted from the parent nucleus.
emission of the nucleus :
+ + + Q
It is given that:
Atomic mass m ( = 22.994466 u
Atomic mass m ( = 22.989770 u
Mass of an electron, = 0.000548 u
Q value of the given r
Similar Questions for you
Q = [4 *4.0026 – 15.9994] *931.5 MeV
Q = 10.2 MeV
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Physics Ncert Solutions Class 12th 2023
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