13.14 The nucleus Ne1023 decays by β- emission. Write down the β -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that:

m ( Ne1023) = 22.994466 u

m ( Na)1123 = 22.989770 u.

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7 months ago

13.14 In β- emission, the number of protons increase by 1 and one electron and an antineutrino are emitted from the parent nucleus.

β- emission of the nucleus Ne1023 :

Ne1023 Na1123 + e- + ν? + Q

It is given that:

Atomic mass m ( Ne1023) = 22.994466 u

Atomic mass m ( Na)1123 = 22.989770 u

Mass of an electron, me = 0.000548 u

Q value of the given r

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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