Find the mass number of an atom whose radius is half of that of a given atom of mass number 192.

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Alok Kumar Singh | Contributor-Level 10

4 months ago

$r = R_{0} {(192)}^{\frac{1}{3}}$

$\frac{r}{2} = R_{0} {(m)}^{\frac{1}{3}}$

$m = \frac{192}{8} = 24$

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Physics Ncert Solutions Class 12th 2023

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