13.16 Suppose, we think of fission of a Fe2656 nucleus into two equal fragments, Al1328 . Is the fission energetically possible? Argue by working out Q of the process. Given

m ( Fe2656) = 55.93494 u and m ( Al1328) = 27.98191 u.

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7 months ago

13.16 The fission can be shown as:

Fe26562Al1328 

It is given that atomic mass

m ( Fe2656)= 55.93494 u

m ( Al1328)= 27.98191 u

The Q-value of this reaction is given as:

Q = mFe2656-2m(Al1328)c2

= 55.93494-2*27.98191c2

= -0.02888 c2

= -0.02888*931.5  MeV

= - 26.902 MeV

The Q value of the fission is negative, therefore the fission is not possible energetically. Q value needs to be posit

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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