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Physics Ncert Solutions Class 12th Physics Class 12th Nuclei

13.16 Suppose, we think of fission of a ${}_{26}^{56}{F e}$ nucleus into two equal fragments, ${}_{13}^{28}{A l}$ . Is the fission energetically possible? Argue by working out Q of the process. Given

m ( ${}_{26}^{56}{F e})$ = 55.93494 u and m ( ${}_{13}^{28}{A l})$ = 27.98191 u.

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Payal Gupta | Contributor-Level 10

3 months ago

13.16 The fission can be shown as:

${}_{26}^{56}{F e} \to 2 {}_{13}^{28}{A l}$

It is given that atomic mass

m ( ${}_{26}^{56}{F e})$ = 55.93494 u

m ( ${}_{13}^{28}{A l})$ = 27.98191 u

The Q-value of this reaction is given as:

Q = $[m ({}_{26}^{56}{F e}) - 2 m ({}_{13}^{28}{A l})] c^{2}$

= $[55.93494 - 2 \times 27.98191] c^{2}$

= -0.02888 $c^{2}$

= -0.02888 $\times 931.5$ MeV

= - 26.902 MeV

The Q value of the fission is negative, therefore the fission is not possible energetically. Q value needs to be positive for a fission.

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13.16 Suppose, we think of fission of a ${}_{26}^{56}{F e}$ nucleus into two equal fragments, ${}_{13}^{28}{A l}$ . Is the fission energetically possible? Argue by working out Q of the process. Given

m ( ${}_{26}^{56}{F e})$ = 55.93494 u and m ( ${}_{13}^{28}{A l})$ = 27.98191 u.

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13.16 Suppose, we think of fission of a Fe2656 nucleus into two equal fragments, Al1328 . Is the fission energetically possible? Argue by working out Q of the process. Given m ( Fe2656) = 55.93494 u and m ( Al1328) = 27.98191 u.

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13.16 Suppose, we think of fission of a ${}_{26}^{56}{F e}$ nucleus into two equal fragments, ${}_{13}^{28}{A l}$ . Is the fission energetically possible? Argue by working out Q of the process. Given

m ( ${}_{26}^{56}{F e})$ = 55.93494 u and m ( ${}_{13}^{28}{A l})$ = 27.98191 u.