13.22 For the β+ (positron) emission from a nucleus, there is another competing process known as electron capture (electron from an inner orbit, say, the K–shell, is captured by the nucleus and a neutrino is emitted).


 e+XZA
Y + v z - 1 A

Show that if β++emission is energetically allowed, electron capture is necessarily allowed but not vice–versa.

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    Answered by

    Payal Gupta | Contributor-Level 10

    3 months ago

    13.22 Let the amount on energy released during the electron capture process be Q1 . The nuclear reaction can be written as:

     e++ XZA Y + v z - 1 A + Q 1 …………………….(1)

    Let the amount of energy released during the positron capture process be Q2. The nuclear reaction can be written as:

     XZA Y+e++vz-1A +Q2 …………………….(2)

    Let us assume

    m N X Z A = Nuclear mass of X Z A

    m N X Z A = Atomic mass of X Z A

    m N Y Z - 1 A = Nuclear mass of Y Z - 1 A

    m N Y Z - 1 A = Atomic mass of Y Z - 1 A

    m e = mass of the electron

    c = speed of light

     

    Q-value of the electron capture reaction is given as:


    Q1 = [ mNXZA+me-mNYZ-1A]c2

    = [ mXZA-Zme+me-mYZ-1A+(Z-1)me]c2

    = [mXZA-mYZ-1A]c2  …&hel

    ...more

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The reaction is X²? → Y¹²? + Z¹²?
Binding energies per nucleon are: X=7.6 MeV, Y=8.5 MeV, Z=8.5 MeV.
Gain in binding energy (Q) = (Binding energy of products) - (Binding energy of reactants)
Q = (120 × 8.5 + 120 × 8.5) - (240 × 7.6) MeV
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