13.25 A source contains two phosphorous radio nuclides P 15 32 , T 1 / 2 = 14.3d and P 15 33 , T 1 / 2 = 25.3d. Initially, 10% of the decays come from P 15 33 . How long one must wait until 90% do so?

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9 months ago

13.25 Half life of P 15 32 , T 1 / 2 = 14.3 days

Half life of P 15 33 , T 1 / 2  = 25.3days and P 15 33  decay is 10% of the total amount of decay

The source has initially 10 % of P 15 33 nucleus and 90% of P 15 32  nucleus

Suppose after t days, the source has 10% of P 15 32  nucleus and 90% of P 15 33  nucleus

Initially:

Number of P 15 33 nucleus = N

Number of P 15 32  nucleus

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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