13.27 Consider the fission of U 92 238 by fast neutrons. In one fission event, no neutrons are emitted and the final end products, after the beta decay of the primary fragments, are C e 58 140 and R u 44 99 )   . Calculate Q for this fission process. The relevant atomic and particle masses are

m( U 92 238 ) =238.05079 u

m( C e 58 140 ) =139.90543 u

m( R u 44 99 )  = 98.90594 u

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7 months ago

13.27 In the fission of U 92 238 , β - 10  particles decay from the parent nucleus. The nuclear reaction can be written as:

U 92 238 + n C e + 58 140 0 1 R u + 10 e - 1 0 44 99

It is given that:

Mass of a U 92 238 n u c l e u s , m 1 = 238.05079 u

Mass of a C e 58 140 n u c l e u s , m 2 =139.90543 u

Mass of a R u 44 99 n u c l e u s , m 3 = 98.90594 u

Mass of a neutron n 0 1 , m 4 = 1.00865 u

 

Q value of the above equation,

Q = m ' U 92 238 + m ' ( n ) - m ' ( 0 1 C e ) - m ' ( R u ) - 10 m e 44 99 58 140 c 2

Where

m' = represents t

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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