13.29 Obtain the maximum kinetic energy of -particles, and the radiation frequencies of decays in the decay scheme shown in Fig. 13.6. You are given that
m( ) = 197.968233 u
m( ) =197.966760 u

13.29 Obtain the maximum kinetic energy of -particles, and the radiation frequencies of decays in the decay scheme shown in Fig. 13.6. You are given that
m( ) = 197.968233 u
m( ) =197.966760 u

13.29 It can be observed from the given decay diagram that decays from 1.088 MeV energy level to the 0 MeV energy level.
Hence the energy corresponding to decay is given as:
= 1.088 – 0 = 1.088 MeV = 1.088 eV = 1.088 J
= 1.7408 J
We know, , where
= Frequency of radiation radiated by d
Similar Questions for you
Q = [4 *4.0026 – 15.9994] *931.5 MeV
Q = 10.2 MeV
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Physics Ncert Solutions Class 12th 2023
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