13.29 Obtain the maximum kinetic energy of β -particles, and the radiation frequencies of  decays in the decay scheme shown in Fig. 13.6. You are given that

m( A u 198 ) = 197.968233 u

m( H g 198 ) =197.966760 u

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7 months ago

13.29 It can be observed from the given γ - decay diagram that γ 1 decays from 1.088 MeV energy level to the 0 MeV energy level.

Hence the energy corresponding to  decay is given as:

 = 1.088 – 0 = 1.088 MeV = 1.088 * 10 6  eV = 1.088 * 10 6 * 1.6 * 10 - 19 J

= 1.7408 * 10 - 13 J

We know, E 1 = h ν 1 , where

ν 1 = Frequency of radiation radiated by γ 1  d

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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