13.5 An air bubble of volume 1.0 cm3 rises from the bottom of a lake 40 m deep at a temperature of 12 °C. To what volume does it grow when it reaches the surface, which is at a temperature of 35 °C?
13.5 An air bubble of volume 1.0 cm3 rises from the bottom of a lake 40 m deep at a temperature of 12 °C. To what volume does it grow when it reaches the surface, which is at a temperature of 35 °C?
-
1 Answer
-
13.5 Volume of the air bubble = 1.0 = 1
Height achieved by bubble, d = 40 m
Temperature at a depth of 40 m, = 12 = 285 K
Temperature at the surface of the lake, = 35 = 308 K
The pressure at the surface of the lake, = 1 atm = 1.013 Pa
The pressure at 40m depth: = 1 atm + d
Where is the density of water = kg/
G = acceleration due to gravity = 9.8 m/
Hence = 1.013 = 493300 Pa
From the relation = , where is the volume of bubble when it
...more
Similar Questions for you
PV = nRT
->Pµn
->Ratio=
T = 20 K
T = –253°C
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers