13.6 Write nuclear reaction equations for

(i) α -decay of Ra88226

(ii) α -decay of Pu94242

(iii) β –-decay of P1532

(iv) β –-decay of Bi83210

(v) β +decay of C611

(vi) β –-decay of Tc4397

(vii) Electron capture of Xe54120

2 Views|Posted a year ago
Asked by Shiksha User
1 Answer
P
a year ago

13.6 In α - decay, there is a loss of 2 protons and 4 neutrons. In every β+ decay, there is a loss of 1 proton and a neutrino is emitted from the nucleus. In every β- decay, there is a gain of 1 proton and an antineutrino is emitted from the nucleus.

Ra88226 → Rn86222 + He24

Pu94242 → U92238 + He24

P1532 → S1632 + e- + ν?

Bi83210 → Po84210 + e- + ν?

C611 → B511 + e+ + ν

Tc4397 → Mo4297 + e+ + ν

Xe54120→ I53120 + ν

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

A = A 0 e − λ t 1     [Radio active decay law]

A 5 = A 0 e − λ ( t 2 − t 1 )

⇒ A v e r a g e     l i f e = 1 λ = ( t 2 − t 1 ) l n 5  

          

...Read more

f o r     A , t 1 2 = 4     s e c  

= m A 0 e − 0 . 6 9 3 4 × 1 6

m A = m A 0 e − 4 × 0 . 6 9 3    -(1)

for B,

for B,  t 1 2 = 8 s e c  

m B = m B 0 e − 2 × 0 . 6 9 3               -(2)

m A m B = m A O m B O e − 4 × 0 . 6 9 3 e − 2 × 0 . 6 9 3

m A m B = 2 5 1 0 0 = x 1 0 0 x = 2 5

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

67K
Colleges
|
1.2K
Exams
|
7.2L
Reviews
|
1.9M
Answers

Learn more about...

Physics Ncert Solutions Class 12th 2026

Physics Ncert Solutions Class 12th 2026

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering