14.10 In a p-n junction diode, the current I can be expressed as

where I0 is called the reverse saturation current, V is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, $k_{B}$

**is the Boltzmann constant (8.610–5 eV/K) and T is the absolute temperature. If for a given diode I0 = 5 10–12 A and T = 300 K, then

(a) What will be the forward current at a forward voltage of 0.6 V?

(b) What will be the increase in the current if the voltage across the diode is increased to 0.7 V?

(c) What is the dynamic resistance?

(d)** What will be the current if reverse bias voltage changes from 1 V to 2 V?

5 Views|Posted 9 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Payal Gupta | Contributor-Level 10

7 months ago

14.10 In a p-n junction diode, the expression for current is given as:

$I = I_{0} e x p (\frac{e V}{2 k_{B} T} - 1)$

Where, $I_{0}$ = Reverse saturation current = 5 $* 10^{- 12}$ A

T = Absolute temperature = 300 K

$k_{B}$ = Boltzmann constant = 8.6 $* 10^{- 5}$ eV/K = 8.6 $* 10^{- 5} * 1.6 * 10^{- 19}$ J/K = 1.376 $* 10^{- 23} J / K$

V = voltage across the diode

e = charge of an electron = 1.6 $* 10^{- 19}$ C

Forward voltage, V = 0.6V

Current

Upvote

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

1.2K

Exams

6.9L

Reviews

1.8M

Answers

Learn more about...

Physics Ncert Solutions Class 12th 2023

View Exam Details

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

Ask Current Students, Alumni & our Experts

Quick Actions

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Have a question related to your career & education?

See what others like you are asking & answering

Similar Questions for you