.14.18 A cylindrical piece of cork of density of base area A and height h floats in a liquid of density ρl .The cork is depressed slightly and then released. Show that the cork oscillates up and down simple harmonically with a period

T = 2 πhρρlg

where ρ is the density of cork. (Ignore damping due to viscosity of the liquid).

0 3 Views | Posted 5 months ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    5 months ago

    Base area of the cork = A

    Height of the cork = h

    Density of the liquid = ρl

    Density of the cork = ρ

    In equilibrium, Weight of the cork = Weight of the liquid displaced by the floating cork

    Let the cork be depressed slightly by an amount x, as a result, some extra water of a certain volume is displaced. Hence, an extra up-thrust acts upward and provides restoring force to the cork.

    Up-thrust (Restoring force) = weight of the extra water displaced

    F = mg = ρlVg

    Volume = Area × distance through which the cork is depressed

    V = Ax

    F = A ρlgx ….(i)

    According to force law, F= kx, where k is constant

    k = Fx = A ρlg&

    ...more

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