14.25 A mass attached to a spring is free to oscillate, with angular velocity ω , in a horizontal plane without friction or damping. It is pulled to a distance x0 and pushed towards the centre with a velocity v0 at time t = 0. Determine the amplitude of the resulting oscillations in terms of the parameters ω,x0 and v0 .

[Hint : Start with the equation x = a cos ( ω t + θ ) and note that the initial velocity is negative.]

0 2 Views | Posted 5 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    5 months ago

    The displacement equation for an oscillating mass is given by : x = Acos ( ωt+θ) , where

    A = the amplitude

    x = the displacement

    θ=phaseconstant

    Velocity, V = dxdt = -A ωsin?(ω t + θ)

    At t = 0, x = x0 , x0=Acos?θ = x0 ….(i)

    And dxdt = -v0 = A ωsin?θ …….(ii)

    Squaring and adding, we get

    A2cos2θ+sin2θ=x02+(v02ω2) , A = x02+(v0ω)2

Similar Questions for you

V
Vishal Baghel

T = 2 π l g

2 = 2 π 2 g

g = 2 π 2 m / s 2

V
Vishal Baghel

Velocity of block in equilibrium, in first case,

v = A ω = A . k M

Velocity of block in equilibrium, is second case,

v ' = A ' ω ' = A ' k M + m

From conservation of momentum,

Mv = (M + m) v’

M A k M = ( M + m ) A ' k M + m A ' = A M M + m

V
Vishal Baghel

f? = 300 Hz
3rd overtone = 7f? = 2100 Hz

V
Vishal Baghel

Kindly consider the following figure

V
Vishal Baghel

K = U

½ mω² (A² - x²) = ½ mω²x²

A² - x² = x²

A² = 2x²

x = ± A/√2

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 686k Reviews
  • 1800k Answers

Learn more about...

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post