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6.10 A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10^–4 T and the dip angle is 30°.

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Payal Gupta | Contributor-Level 10

5 months ago

6.10 Speed of the jet plane, v = 1800 km/h = 500 m/s

Wing span, l = 25 m

Earth’s magnetic field, B = 5 $\times 10^{- 4}$ T

Dip angle, $β$ = 30 $°$

The vertical component of the earth’s magnetic field, $B_{V}$ = B $\sin ? β$ = 5 $\times 10^{- 4} \sin ? 30 °$ = 2.5 $\times 10^{- 4}$ T

Voltage difference between the ends of the wing can be calculated as

e = $B_{V} \times l \times v$ = 2.5 $\times 10^{- 4} \times 25 \times 500$ = 3.125 V

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6.10 A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10^–4 T and the dip angle is 30°.

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6.10 A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10–4 T and the dip angle is 30°.

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6.10 A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10^–4 T and the dip angle is 30°.