6.10 A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth's magnetic field at the location has a magnitude of 5 * 10–4 T and the dip angle is 30°.
6.10 A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth's magnetic field at the location has a magnitude of 5 * 10–4 T and the dip angle is 30°.
6.10 Speed of the jet plane, v = 1800 km/h = 500 m/s
Wing span, l = 25 m
Earth's magnetic field, B = 5 T
Dip angle, = 30
The vertical component of the earth's magnetic field, = B = 5 = 2.5 T
Voltage difference between the ends of the wing can be calculated as
e = = 2.5 = 3.125 V
Similar Questions for you
Kindly go through the solution
Bv = B sin 60°
->
M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?
(A) The magnet's entry
R =
L = 2 mH
E = 9V
Just after the switch ‘S’ is closed, the inductor acts as open circuit.
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Physics Ncert Solutions Class 12th 2023
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