6.15 An air-cored solenoid with length 30 cm, area of cross-section 25 cm2 and number of turns 500, carries a current of 2.5 A. The current is suddenly switched off in a brief time of 10–3 s. How much is the average back emf induced across the ends of the open switch in the circuit? Ignore the variation in magnetic field near the ends of the solenoid.

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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    6.15 Length of the solenoid, l = 30 cm = 0.3 m

    Area of cross-section, A = 25 cm2 = 25 ×10-4 m2

    Number of turns on the solenoid, N = 500

    Current in the solenoid, I = 2.5 A

    Current flowing time, t = 10-3 s

    We know average back emf, e = ddt …………………. (1)

    Where d= Change in flux = NAB ……………… .(2)

    B = Magnetic field strength = μ0NIl ………………. (3)

    Where μ0 = Permeability of free space = 4 π×10-7 T m A-1

    From equation (1) and (2), we get

    e = NABdt = NAdt×μ0NIl = μ0N2AIlt&nb

    ...more

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