6.17 A line charge l per unit length is lodged uniformly onto the rim of a wheel of mass M and radius R. The wheel has light non-conducting spokes and is free to rotate without friction about its axis (Fig. 6.22). A uniform magnetic field extends over a circular region within the rim. It is given by,

B = – B0 k  (r  a; a < R)

= 0 (otherwise)

What is the angular velocity of the wheel after the field is suddenly switched off?

0 3 Views | Posted 4 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    6.17 Line charge per unit length = λ = TotalchargeLength = Q2πr

    Where r = distance of the point within the wheel

    Mass of the wheel = M

    Radius of the wheel = R

    Magnetic field, B? = -B0k?

    At a distance r, the magnetic force is balanced by the centripetal force. i.e.

    BQ v = Mv2r , where v = linear velocity of the wheel. Then,

    ×2λπr = Mvr

    v = 2Bλπr2M

    Angular velocity, ω=vR = 2Bλπr2MR

    For r aR,weget ω=-2B0λπa2MRk?

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