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Electromagnetic Induction Ncert Solutions Physics Class 12th Physics Ncert Solutions Class 12th Physics Class 12th Electromagnetic Induction

6.8 Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit.

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Payal Gupta | Contributor-Level 10

4 months ago

6.8 Given:

Initial current, $I_{1}$ = 5.0 A

Final current, $I_{2}$ = 0 A

Change in current, di = $I_{1} - I_{2}$ = 5 A

Time taken for the change, dt = 0.1 s

Average emf, e = 200 V

For self-inductance (L) of the coil, L is given by

L = $\frac{e}{\frac{d i}{d t}}$ = $\frac{200}{\frac{5}{0.1}}$ = 4 H

Hence, the self-inductance of the coil is 4 H.

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6.8 Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit.

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