7.15 A 100 μF capacitor in series with a 40 Ω resistance is connected to a 110 V, 60 Hz supply.

(a) What is the maximum current in the circuit?

(b) What is the time lag between the current maximum and the voltage maximum?

3 Views|Posted 8 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Payal Gupta | Contributor-Level 10

8 months ago

7.15 Capacitance of the capacitor, C = 100 $μ F$ = 100 $* 10^{- 6}$ F

Resistance of the resistor, R = 40 Ω

Supply voltage, V = 110 V

Frequency of the supply voltage, $ν$ = 60 Hz

Angular frequency, $ω$ = 2 $π ν$ = 2 $π * 60$ rad/s

For a RC circuit, the impedance Z, is given by Z = $\sqrt[]{R^{2} + \frac{1}{ω^{2} C^{2}}}$

Z = $\sqrt[]{40^{2} + \frac{1}{{(2 π * 60)}^{2} {* (100 * 10^{- 6})}^{2}}}$ = 47.996 Ω

Peak voltage, $V_{0}$ = $\sqrt 2 * V$ = $\sqrt 2 * 110$ = 155.56 V

Peak current,

Upvote

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

1.2K

Exams

6.8L

Reviews

1.8M

Answers

Learn more about...

Physics Ncert Solutions Class 12th 2023

View Exam Details

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

Ask Current Students, Alumni & our Experts

Quick Actions

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Have a question related to your career & education?

See what others like you are asking & answering

7.15 A 100 μF capacitor in series with a 40 Ω resistance is connected to a 110 V, 60 Hz supply. (a) What is the maximum current in the circuit? (b) What is the time lag between the current maximum and the voltage maximum?

Similar Questions for you