Search Colleges, Courses, Exams, Questions and Articles

Ask a query on 8879100846 Ask Login | Sign Up

 

 

› Ask & Answer › Question

7.24 At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m3s–1. If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 ms–2 ).

0 4 Views | Posted 4 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    7.24 Height of the water pressure head, h = 300 m

    Volume of water flow rate, V = 100 m3 /s

    Efficiency of turbine generator,  η = 60 % = 0.6

    Acceleration due to gravity, g = 9.8 m/ s2

    Density of water,  ρ = 103 kg/ m3

    Therefore, electric power available from the plant = η ×hρgV

    = 0.6 ×300×103×9.8×100

    = 176.4 ×106 W

    = 176.4 MW

Similar Questions for you

A coil has resistance of 30 ohm and inductive reactance 20 ohm at 50 Hz frequency. If an ac source of 200 V, 100 Hz is connected across the coil, current in coil will be
A
alok kumar singh

Kindly go through the solution

 

Two bodies of mass 10 kg and 2 kg are moving with velocities m/s and m/s respectively. The velocity of their centre of mass is

 
A
alok kumar singh

Kindly go through the solution

 

A capacitor having capacitance of 100 µF is charged with a potential difference of 12 V is connected to an inductor of inductance 10 mH. Find the maximum current through the inductor.
A
alok kumar singh

I = Q 0 . ω            

= C V L C = V C L

= 1 2 1 0 0 × 1 0 − 6 1 0 × 1 0 − 3

= 1.2 A

In AC circuit with source voltage e = 20 sin 1000 t is connected to series L – R circuit whose power factor is 1 2 . If E = 25 sin 2000 t, the new power factor is
A
alok kumar singh

Lω = 1000 L                            Lω = R.

New

R = 1000 L

2000 L

c o s θ = R Z

= 1 0 0 0   L ( 1 0 0 0   L ) 2 + ( 2 0 0 0 ?   L ) 2

= 1 1 + 4 = 1 5

 

Find average power in electric circuit if source voltage (V) = 20sin(100wt) and current in the circuit (I) = 2sin(100wt + π 3 )
A
alok kumar singh

= IV cosf

= 2 0 2 * 2 2 *  cos 60°

= 10 W

 

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 687k Reviews
  • 1800k Answers

Learn more about...

Share Your College Life Experience

Write a Review

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Ask Now
Community GuidelinesUser Points System
QuestionsDiscussionsTags
×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post