7.4 A 60 μF capacitor is connected to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit.

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Payal Gupta | Contributor-Level 10

8 months ago

7.4 Capacitance of the capacitor, C = 60 $μ F$ = 60 $* 10^{- 6}$ F

Supply voltage, V = 110 V

Supply frequency, $ν$ = 60 Hz

Angular frequency, $ω$ = 2 $π ν$

Capacitive reactance, $X_{c}$ = $\frac{1}{ω C}$ = $\frac{1}{2 π ν C}$

rms value of current is given by I = $\frac{V}{X_{c}}$ = 110 $* 2 * π * 60 *$ 60 $* 10^{- 6}$ = 2.49 A

Hence, the rms value of current is 2.49 A.

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Physics Ncert Solutions Class 12th 2023

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