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7.5 In Exercises 7.3 and 7.4, what is the net power absorbed by each circuit over a complete cycle. Explain your answer.

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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    7.5 In the inductive circuit:

    rms value of current, I = 15.92 A

    rms value of voltage, V = 220 V

    The net power absorbed can be obtained by

    P = VI cos ∅ , where ∅ is the phase difference between alternating voltage and current = 90 °

    So P = VI cos 90° = 0

    In the capacitive circuit:

    rms value of current, I = 2.49 A

    rms value of voltage, V = 110 V

    The net power absorbed can be obtained by

    P = VI cos ∅ , where ∅ is the phase difference between alternating voltage and current = 90 °

    So P = VI cos 90° = 0

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