Physics Ncert Solutions Class 12th Alternating Current Overview Class 12th Physics Alternating Current

7.7 A charged 30 μF capacitor is connected to a 27 mH inductor. What is the angular frequency of free oscillations of the circuit?

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Payal Gupta | Contributor-Level 10

8 months ago

7.7 Capacitance of the capacitor, C = 30 $μ F$ = 30 $* 10^{- 6}$ F

Inductance of the Inductor, L = 27 mH = 27 $* 10^{- 3}$ H

Angular frequency is given as

$ω_{r}$ = $\frac{1}{\sqrt[]{L C}}$ = $\frac{1}{\sqrt[]{27 * 10^{- 3} * 30 * 10^{- 6}}}$ = 1.11 $10^{3}$ rad /s

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$I = Q_{0 . ω}$

$= \frac{C V}{\sqrt[]{L C}} = V \sqrt[]{\frac{C}{L}}$

$= 12 \sqrt[]{\frac{100 \times 1 0^{- 6}}{10 \times 1 0^{- 3}}}$

= 1.2 A

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Physics Ncert Solutions Class 12th 2023

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