8.19 A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the earth’s gravitational influence? Mass of the satellite = 200 kg; mass of the earth = 6.0×1024 kg; radius of the earth = 6.4 × 106 m; G = 6.67 × 10–11 N m2 kg2.

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    Vishal Baghel | Contributor-Level 10

    4 months ago

    Mass of the Earth, M = 6.0 * 1024 kg

    Mass of the satellite, m = 200 kg

    Radius of the Earth, Re = 6.4 *106 m

    Universal gravitational constant, G = 6.67 * 10–11 N m2 kg2

    Height of the satellite, h = 400 km = 0.4 *106 m

    Total energy of the satellite at height h = 12mv2 + ( -GMemRe+h )

    Orbital velocity of the satellite, v = GMeRe+h

    Total energy of the satellite at height h = m2 ( GMeRe+h) - ( GMemRe+h ) = - 12(GMemRe+h)

    The negative sign indicates that the satellite is bound to the Earth. This is called bound energy of the satellite Typee quationhere.

    Energy require to send the satellite out of its orbit = - (bound energy) = 12(GMemRe+h)

    =&nb

    ...more

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