8.19 A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the earth’s gravitational influence? Mass of the satellite = 200 kg; mass of the earth = 6.0×1024 kg; radius of the earth = 6.4 × 106 m; G = 6.67 × 10–11 N m2 kg–2.
8.19 A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the earth’s gravitational influence? Mass of the satellite = 200 kg; mass of the earth = 6.0×1024 kg; radius of the earth = 6.4 × 106 m; G = 6.67 × 10–11 N m2 kg–2.
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1 Answer
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Mass of the Earth, M = 6.0 * 1024 kg
Mass of the satellite, m = 200 kg
Radius of the Earth, = 6.4 *106 m
Universal gravitational constant, G = 6.67 * 10–11 N m2 kg–2
Height of the satellite, h = 400 km = 0.4 m
Total energy of the satellite at height h = + ( )
Orbital velocity of the satellite, v =
Total energy of the satellite at height h = ( - ( ) =
The negative sign indicates that the satellite is bound to the Earth. This is called bound energy of the satellite
Energy require to send the satellite out of its orbit = - (bound energy) =
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