8.25 A rocket is fired ‘vertically’ from the surface of mars with a speed of 2 km s–1. If 20% of its initial energy is lost due to Martian atmospheric resistance, how far will the rocket go from the surface of mars before returning to it? Mass of mars = 6.4×1023 kg; radius of mars = 3395 km; G = 6.67×10-11 N m2 kg–2.
8.25 A rocket is fired ‘vertically’ from the surface of mars with a speed of 2 km s–1. If 20% of its initial energy is lost due to Martian atmospheric resistance, how far will the rocket go from the surface of mars before returning to it? Mass of mars = 6.4×1023 kg; radius of mars = 3395 km; G = 6.67×10-11 N m2 kg–2.
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1 Answer
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Initial kinetic energy of the rocket =
Initial potential energy of the rocket =
Total initial energy =
If 20% of initial kinetic energy is lost due to Martian atmosphere resistance, then only 80% of its kinetic energy helps in reaching a height
Total initial energy available = 0.8
Maximum height reached by the rocket = h
At this height, the velocity and hence the kinetic energy of the rocket becomes zero.
Total energy of the rocket at height h =
Applying the law of conservation of energy for the rocket, we can write:
0.4 =
0.4 = GM(
0.4 = GM( )
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