9.32 Figure 9.34 shows an equiconvex lens (of refractive index 1.50) in contact with a liquid layer on top of a plane mirror. A small needle with its tip on the principal axis is moved along the axis until its inverted image is found at the position of the needle. The distance of the needle from the lens is measured to be 45.0 cm. The liquid is removed and the experiment is repeated. The new distance is measured to be 30.0 cm. What is the refractive index of the liquid?

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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    9.32 Focal length of the convex lens, f1 = 30 cm

    The liquid acts as a mirror, focal length of the liquid = f2

    Focal length of the system (convex lens + liquid), f = 45 cm

    For a pair of optical systems placed in contact, the equivalent focal length is given as

    1f = 1f1 + 1f2 or 1f2=1f-1f1 = 145 - 130

    f2= - 90 cm

    Let the refractive index of the lens be μ1 and the radius of curvature of one surface be R

    Hence, the radius of curvature of the other surface is –R

    R can be obtained by using the relation

    1f1 = ( μ1-1)(1R + 1R ) = (1.5 – 1)( 2R)

    130 = 1R ,

    ...more

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