A 1 m long copper wire carries a current of 1 A. If the cross section of the wire is 2.0mm² and the resistivity of copper is 1.7 × 10^-8 $\Omega m,$  the force experienced by moving electron in the wire is _______× 10^-23N.

i = 1 A $j=\sigma E$

A = 2mm²

$\rho =1.7\times 10^{-8}\Omega m$ $F=eE=\frac{ej}{\sigma }=\frac{ei}{A\sigma }=\frac{ei\rho }{A}$

= $\frac{1.6\times 10^{-19}\times 1.7\times 10^{-8}}{2\times 10^{-6}}$

= 136 × 10^-23 N

<p>i = 1 A&nbsp;<math><mrow><mi>j</mi><mo>=</mo><mi>σ</mi><mi>E</mi></mrow></math></p><p>A = 2mm²</p><p><math><mrow><mi>ρ</mi><mo>=</mo><mn>1</mn><mo>.</mo><mn>7</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mo>−</mo><mn>8</mn></mrow></msup><mi>Ω</mi><mi>m</mi></mrow></math>&nbsp;<math><mrow><mi>F</mi><mo>=</mo><mi>e</mi><mi>E</mi><mo>=</mo><mfrac><mrow><mi>e</mi><mi>j</mi></mrow><mrow><mi>σ</mi></mrow></mfrac><mo>=</mo><mfrac><mrow><mi>e</mi><mi>i</mi></mrow><mrow><mi>A</mi><mi>σ</mi></mrow></mfrac><mo>=</mo><mfrac><mrow><mi>e</mi><mi>i</mi><mi>ρ</mi></mrow><mrow><mi>A</mi></mrow></mfrac></mrow></math></p><p>=&nbsp;<math><mrow><mfrac><mrow><mn>1</mn><mo>.</mo><mn>6</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mo>−</mo><mn>1</mn><mn>9</mn></mrow></msup><mo>×</mo><mn>1</mn><mo>.</mo><mn>7</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mo>−</mo><mn>8</mn></mrow></msup></mrow><mrow><mn>2</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mo>−</mo><mn>6</mn></mrow></msup></mrow></mfrac></mrow></math></p><p>= 136 × 10^-23 N</p><div class="photo-widget-full"><div class="figure"><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1753604243phpSUTRYx.jpeg" alt="" width="235" height="58" loading="lazy"></picture></div></div>

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