A ball is projected from ground at angle q with the horizontal. After t = 1 s, it is moving at 45° with the horizontal and after t = 2 second, it is moving horizontally. What is speed of projection of ball? [g = 10 m s–2]

 

 

Option 1 -

1

Option 2 -

2

Option 3 -

3

Option 4 -

4

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  • 1 Answer

  • Correct Option - 4


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V
Vishal Baghel

  a = v 0 2 R

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R 1 = 1 . 2 1 R

 

V
Vishal Baghel

v? = 3tî v? = 24cos 60°î + 24sin 60°? = 12î + 12√3?
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Vishal Baghel

ω = θ² + 2θ
α = (ωdω)/dθ = (θ² + 2θ) (2θ + 2)
At θ = 1rad.
ω = 3rad/s and α = 12rad/s²
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Vishal Baghel

a? = v? ²/4r
a_A? = (v? ²/r²) × r = v? ²/r
a_A = 3v? ²/4r

V
Vishal Baghel

a = ω²l = (2π/T)²l = (2π/60)²×0.1 = 1.1×10? ³ m/s²

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