A ball is projected with a velocity,
, at an angle of
with the vertical direction, its speed at the highest pint of its trajectory will be :
A ball is projected with a velocity,
, at an angle of
with the vertical direction, its speed at the highest pint of its trajectory will be :
Option 1 -
zero
Option 2 -
Option 3 -
Option 4 -
-
1 Answer
-
Correct Option - 2
Detailed Solution:At the highest point only horizontal component of velocity remains
Similar Questions for you
Using whetstone
Let V? = 10V, V? = xV, V? = 0V, and V? = yV.
Applying Kirchhoff's current law at node B:
(x - 10)/100 + (x - y)/15 + (x - 0)/10 = 0 ⇒ 53x - 20y = 30 . (1)
Applying Kirchhoff's current law at node D:
(y - 10)/60 + (y - x)/15 + (y - 0)/5 = 0 ⇒ 17y - 4x = 10 . (2)
Solving equations (1) and (2), we get:
x = 0.865 and y = 0.792
The current i? is:
i? = (x - y) / 15 = 4.87 mA
= 2.4k = 2400
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