A ball is projected with a velocity, $10 {m s}^{- 1}$ , at an angle of $60^{?}$ with the vertical direction, its speed at the highest pint of its trajectory will be :

Option 1 - zero

Option 2 - <math> <mn>5</mn> <mroot> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> <mrow></mrow> </mroot> <msup> <mrow> <mrow> <mtext> </mtext> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </mrow> </msup> </math>

Option 3 - <math> <mn>5</mn> <msup> <mrow> <mrow> <mtext> </mtext> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </mrow> </msup> </math>

Option 4 - <math> <mn>10</mn> <msup> <mrow> <mrow> <mtext> </mtext> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </mrow> </msup> </math>

2 Views|Posted 5 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Raj Pandey | Contributor-Level 9

5 months ago

Correct Option - 2

Detailed Solution:

At the highest point only horizontal component of velocity remains $\Rightarrow u_{x} = u c o s ? θ$

Upvote

Similar Questions for you

Current measured by the ammeter (A) in the reported circuit when no current flows through $10 Ω$ resistance, will be A.

Raj Pandey

Using whetstone

$\frac{R}{3} = \frac{4}{6} \Rightarrow R = 2 Ω$

$R_{e q u} = \frac{54}{15} Ω$

$i = \frac{36}{\frac{54}{15}} = 10 A$

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15Ω resistance is connected across BD. Calculate the current through the galvanometer when a potential difference of 10V is maintained across AC.


Alok Kumar Singh

Let V? = 10V, V? = xV, V? = 0V, and V? = yV.
Applying Kirchhoff's current law at node B:
(x - 10)/100 + (x - y)/15 + (x - 0)/10 = 0 ⇒ 53x - 20y = 30 . (1)
Applying Kirchhoff's current law at node D:
(y - 10)/60 + (y - x)/15 + (y - 0)/5 = 0 ⇒ 17y - 4x = 10 . (2)
Solving equations (1) and (2), we get:
x =

Raj Pandey

In a meter bridge experiment, for measuring unknown resistance ‘S’, the null point is obtained at a distance 30cm from the left side as shown at point D. If R is 5.6 $k Ω$ , then the value of unknown resistance ‘S’ will be ___________ $Ω .$

Payal Gupta

$\frac{30}{70} = \frac{S}{5.6 k Ω} \Rightarrow S = \frac{3}{7} \times 5.6 k Ω = 3 \times 0.8 k Ω$

= 2.4k $Ω$ = 2400 $Ω$

Four resistance $40 Ω, 60 Ω, 90 Ω$ , and $110 Ω$ make the arms of a quadrilateral ABCD. Across $A C$ is a battery of emf $40 V$ and internal resistance negligible. The potential difference across $B D$ in $V$ is

Alok Kumar Singh

10553.33

Sol. $\frac{1}{λ_{min}} = R [\frac{1}{1} - \frac{1}{\infty}] = R [n = \infty \to n = 1]$

$\frac{1}{λ_{m a x}} = R [\frac{1}{1} - \frac{1}{4}] = \frac{3 R}{4} [n = 2 \to n = 1]$

$\Rightarrow Δ λ \Rightarrow \frac{4}{3 R} - \frac{1}{R} \Rightarrow \frac{1}{3 R} = 340$

For Paschan $\Rightarrow \frac{1}{λ_{min}} = R [\frac{1}{9}] [n = \infty \to h = 3]$

$\Rightarrow \frac{1}{λ_{m a x}} = R [\frac{1}{9} - \frac{1}{16}] = \frac{7 R}{144}$

$\Rightarrow Δ λ = \frac{81}{7 R}$

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

1.2K

Exams

6.9L

Reviews

1.8M

Answers

Learn more about...

Physics Current Electricity 2025

View Exam Details

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

Ask Current Students, Alumni & our Experts

Quick Actions

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Have a question related to your career & education?

See what others like you are asking & answering

A ball is projected with a velocity, 10 m s - 1 , at an angle of 60 ? with the vertical direction, its speed at the highest pint of its trajectory will be :